Question

Three consecutive integers have a sum of
42. Find the integers.

Answer 1

your consecutive integers are : x, x + 1, and x + 2

they equal 42...
x + (x + 1) + (x + 2) = 42 --- combine like terms
3x + 3 = 42 -- subtract 3 from both sides
3x = 42 - 3
3x = 39 -- divide both sides by 3
x = 13

x + 1 = 13 + 1 = 14
x + 2 = 13 + 2 = 15

check..
13 + 14 + 15 = 42
42 = 42 (correct)

so your numbers are : 13,14,and 15