I am currently stuck on a calc two problem. I have tried several different variations of the current answers entered all are wrong. Any help with this problem would be greatly appreciated. The problem is in the image below.

Thank You

Question

I am currently stuck on a calc two problem. I have tried several different variations of the current answers entered all are wrong. Any help with this problem would be greatly appreciated. The problem is in the image below.

Thank You

anonymous · Answer

attachment

irishboy123 · Answer

there are least 2 mistakes here

you want $\vec r = \vec r_o + \vec v \; t $ so $\vec r_o$ should be the position of the particle at t = 0, not t = 1

and there is an arithmetic error in your calculation of $\vec v$

anonymous · Answer

I have tried to use the initial point R and was still incorrect.

irishboy123 · Answer

but did you check your algebra as i suggested?

anonymous · Answer

yes

anonymous · Answer

don't know where I'm going wrong.

anonymous · Answer

Check your $x$ component again.

anonymous · Answer

Okay so I take the point at the initial R and then take the difference between the two points time t. So 9+(-4-9)t

anonymous · Answer

Right, and what's the coefficient of $t$?