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(2^x+1)/(2^x-1)=5 . please solve
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\[\huge\rm \frac{2^{x+1}}{2^{x-1}}= 5 \] like this ?
the 1 is not in the power
\[(2^x+1)/(2^x-1)=5\]
\[ 2^{x}=a\] substitute in the problem
(a+1)/(a-1) = 5
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a+1 =5(a-1)
a+1 = 5a-5 1+5= 5a-a 6=4a 6/4=a 3/2 =a
a=3/2 but \[a=2^{x}\]
\[2^{x}=3/2\]
is it clear
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