Trigonometry: If sin Θ = 5/6, what are the values of cos Θ and tan Θ? A. cos Θ = ±11/36; tan Θ = ±1/11 B. cos Θ = ± √11/6; tan Θ = -1/11 C. cos Θ = ±11/6; tan Θ = -5/11 D. cos Θ = ± √11/6; tan Θ = ± 5√11/11
SOHCAHTOA.... Form the triangle and use the information that sin theta = 5/6 to figure out the corresponding sides of that triangle.... Solve for the missing side... put it together and presto your done.
SOHCAHTOA sin opposite over hypotenuse cosine adjacent over hypotenuse tangent opposite over adjacent
"and presto you're done" LMAO
Yes, I know SOH CAH TOA. I'm just not sure how to start this problem
:D yea sorry I am reminiscing about the good old days
I'll try drawing it 1 sec.
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How would I solve for the missing side?
Cos (adjacent / hypotenuse )
Ahh but we need a number there in order to use that definition right? Otherwise its cos theta = ? / 6
Ok what do we know about the triangle that.... darn I didnt draw it in... shame on me.
omg you crack me up...
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