36. A student scored an 88, 92, and 76 on three math tests. What does the student need to get on the fourth test to have an average of 85 for all four tests? Joseph wants to use algebra to solve this problem. Which equation should he use? (NOTE: The answers with the “4” or/and “3” under them are fractions)
a. 4x = 256/85
b. 256 + x = 85
4
c. 85 + x = 25
4
d. 256 = 85x
3 4
My answer~d

Question

36.  A student scored an 88, 92, and 76 on three math tests. What does the student need to get on the fourth test to have an average of 85 for all four tests?  Joseph wants to use algebra to solve this problem. Which equation should he use? (NOTE: The answers with the “4” or/and “3” under them are fractions)
a.    4x = 256/85
b.   256 + x = 85
      4
c.    85 + x = 25
       4
d.    256 = 85x
         3        4
My answer~d

campbell_st · Answer

well if x is the missing score 

you have 3 scores and the average of 4 scores needs to be 85

so the equation sets up as 

$$85 = \frac{88 + 92 + 76 + x}{4}$$

so multiply both sides of the equation by 4

$$340 = x + 256$$

now you can some for x

abbycross167 · Answer

so does that mean it's b? or did I get it right?

campbell_st · Answer

well I'd say B is the solution

$$\frac{256 + x}{4} = 85$$

abbycross167 · Answer

ok, thank you soo much!!