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do u need answers or explanation
line which is parallel to y=-2x-7is in the form of y= -2x +k
it passes through the point (3,1) so,substitute x=3 and y=1 in above equation to get k value
1=-2*3 +k 1=-6+k 1+6 =k k=7 therefore ,required equation is y=-2x+7
2)W=6L+50
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may i answer the third one?
why not sure
ArifL r u doing
wut?
answer to the third problem
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it D
equation of the line passing through two points (x1,y1)=(2,9), (x2,y2) =(1,4) is (y-y1)(x2-x1) =(y2-y1) (x-x1)
(y-9)(1-2) =(4-9)(x-2) (y-9)(-1) =(-5)(x-2)
-y+9 = -5x+10 9-10 =-5x+y
-1= -5x+y or -5x+y =-1 i,e last one is the right option
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is it clear
ty and so sorry i was not online ;-;
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