Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

http://prntscr.com/8sjisx http://prntscr.com/8sjj5q http://prntscr.com/8sjjg0

OpenStudy (dayakar):

do u need answers or explanation

OpenStudy (dayakar):

line which is parallel to y=-2x-7is in the form of y= -2x +k

OpenStudy (dayakar):

it passes through the point (3,1) so,substitute x=3 and y=1 in above equation to get k value

OpenStudy (dayakar):

1=-2*3 +k 1=-6+k 1+6 =k k=7 therefore ,required equation is y=-2x+7

OpenStudy (dayakar):

2)W=6L+50

OpenStudy (anonymous):

may i answer the third one?

OpenStudy (dayakar):

why not sure

OpenStudy (dayakar):

ArifL r u doing

OpenStudy (anonymous):

wut?

OpenStudy (dayakar):

answer to the third problem

OpenStudy (anonymous):

it D

OpenStudy (dayakar):

equation of the line passing through two points (x1,y1)=(2,9), (x2,y2) =(1,4) is (y-y1)(x2-x1) =(y2-y1) (x-x1)

OpenStudy (dayakar):

(y-9)(1-2) =(4-9)(x-2) (y-9)(-1) =(-5)(x-2)

OpenStudy (dayakar):

-y+9 = -5x+10 9-10 =-5x+y

OpenStudy (dayakar):

-1= -5x+y or -5x+y =-1 i,e last one is the right option

OpenStudy (dayakar):

is it clear

OpenStudy (anonymous):

ty and so sorry i was not online ;-;

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!