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(ax/x)=b solve for x
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\[\frac{ ax }{ x }=b\]
cancel out the common factor x,\[\large\rm \frac{a\cancel{x}}{\cancel{x}}=b\]Which leads to \(\large\rm a=b\).
Note that x can not equal 0 because we have one in the denominator. But what happens is... Since all of our x's fell out of the equation, Every other x value will satisfy this equation when a and b are the same.
so x can be any number?
Any number `except 0`
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And that's only when a=b. Otherwise, no solutions exist when a and b are different numbers.
Kind of a tricky question, lot of stipulations :)
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