A car starts from the rest (v=0m/s) at the top of a hill. Its put into "Neutral" and pushed so that it starts to roll down the hill. For this situation, Conservation of Energy says:
PE top=m g h = 1/2 m v^2=KE bottom
So when the car get to the bottom of the hill, what is its velocity?
A) Square root of 2gh
B)1/2at^2
C)2ghm^2
D)not enough info

Question

A car starts from the rest (v=0m/s) at the top of a hill. Its put into "Neutral" and pushed so that it starts to roll down the hill. For this situation, Conservation of Energy says:
PE top=m g h = 1/2 m v^2=KE bottom
So when the car get to the bottom of the hill, what is its velocity? 
A) Square root of 2gh
B)1/2at^2
C)2ghm^2
D)not enough info

danjs · Answer

no physics, it all is given, solve for v,

danjs · Answer

you can see velocity as   v^2,   the solution will be root probably

anonymous · Answer

Thank you Dan!