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Calculus III Limit question
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the limit does not exist.
\[\lim_{(x,y) \rightarrow (0,1)}\arctan[\frac{x^2+1}{x^2+(y-1)^2}]\]
did you try L'Hopitals rule?
pi/2
Nope, i am not sure how to use it when there is arctan
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But i was thinking if you sub in (0,1) you will get an undefined angle and that wold be pi/2 radians. I am not sure if this was the correct way to view it.
Nvm, i think i just answered my own question lol
if "But i was thinking if you sub in (0,1) you will get an undefined angle and that wold be pi/2 radians. I am not sure if this was the correct way to view it." is your answer then you might want to continue to think about it.
ikram the link gave me virus
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