Question

http://imgur.com/8tCxyFD
Functions problem. Could help ^_^

Answer 1

to find f(x+1) substitute x for x+1 int of(x) function :=))

Answer 2

\[\huge\rm f(\color{ReD}{x+1})=\color{reD}{x}^2-2\color{Red}{x}\]
replace all x's with x+1

Answer 3

x^2-1

Answer 4

hmm how did you get that please show some work :=))

Answer 5

woulnd it be (x+1)(x+1)-2(x+1)
x^2+x+x+1-2x-2=x^2-1

Answer 6

nice \[\huge\rm \frac{ \color{red}{f(x+h)} -\color{blue}{f(x) }}{ h }\]
now sub that into the formula
\[\huge\rm \frac{ \color{ReD}{x^2 -1} -\color{blue}{ (x^2-2x) }}{ h }\]
first distribute blue parentheses by negative one and then combine like terms

Answer 7

x^2-1-x^2+2x
2x-1?

Answer 8

hmm wait

Answer 9

2x-1/h*

Answer 10

but then we're missing something arent we

Answer 11

hmm i i was thinkg x+h
we can't substitute f(x+h) with f(x+1)
f(x+1) =x^2-1 that's it

Answer 12

now substitute x for `x+h` into f(x) function the we can use \[\huge\rm \frac{ \color{red}{f(x+h)} -\color{blue}{f(x) }}{ h }\] this formula :=)

Answer 13

then*

Answer 14

so x^2-1+h-(x^2-1)/h?

Answer 15

hmm why did u replaced f(x) with x2- 1 ??

Answer 16

\[\huge\rm f(\color{ReD}{x+h})=\color{reD}{x}^2-2\color{Red}{x}\]
substitute all x's for (x+h)

Answer 17

btw that's 2nd part `f(x+h)`

Answer 18

ah.
i see, i can solve it fromhere, thanks!

Answer 19

alright np :=))
good work \o^_^o/

Answer 20

@Nnesha actually gunna be taking the test for all this now, would you mind stickign around to answer my questions if i have any? ^_^ cuz generally i have the concepts down, just a few times i get mixed up

Answer 21

hmm for test
well you can practice few question before taking test
and don't worry you don't have to ask test q you can do it n ur own
be confident :=)

Answer 22

flutter it, let's just say it isnt a test XD

Answer 23

im going to log out few mints or 30 mints later
but if u have any doubt on any test question
try to work on the same problem one or two times

Answer 24

no i'm glad you said it

Answer 25

no need to lie :=))

Answer 26

Ofc, test is 2 hrs anyways.... if u happen to get back before i finish, and i do infact have questions. i usually need just a little boost to get goin. ^_^ I get caught up in thinking too much, that i misread easy problems.

Answer 27

you re pretty good at math subject
you know all the concepts
if we do 99% and 1% from someone help on the test that means u didn't put 100% :=))

Answer 28

ww i see just relax!! :=) you will do fine !

Answer 29

good luck!! :=)) wish u all the best
let me know what you get :=)

Answer 30

btw do you know notifications aren't working ?
you tagged me before but i didn't get the notification... :/

Answer 31

Wth ;-;

Answer 32

what ??

Answer 33

i meant to the notifications not working.. i noticed too

Answer 34

i really like u didn't lie first time :=)trust me you are good at these stuff you can do it you don't need anyone!!

Answer 35

huh i'll see what i can do hmm

Answer 36

can't promise bec i won't be here after 25 mints :=)

Answer 37

nvm pretty much finished lol

Answer 38

Although , if you know how to find the parrellel/perpendicular of a slope etc. i could use info on that in the future <3 failed a exam cuz of dat stuff lol