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OpenStudy (anonymous):
Solve the equation a/a^2-64+3/a-8=2/a+8
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pooja195 (pooja195):
−72a^2+4a=8a^2+2a(Simplify both sides of the equation)
−72a2+4a−(8a^2+2a)=8a^2+2a−(8a^2+2a)(Subtract 8a^2+2a from both sides)
OpenStudy (anonymous):
i doubt it
pooja195 (pooja195):
−80a^2+2a=0
Factor that.
pooja195 (pooja195):
@satellite73 then maybe you should do it.
OpenStudy (anonymous):
\[\frac{a}{a^2-64}+\frac{3}{a-8}=\frac{2}{a+8}\] is my guess
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OpenStudy (anonymous):
course @pooja195 i could be wrong
pooja195 (pooja195):
\[\huge~\rm~\frac{ a }{ a }^2-64+\frac{ 3 }{ a-8}=\frac{ 2 }{ a+8 }\]
I was thinking this :/
(sorry for the attitude lol)
OpenStudy (triciaal):
@maysum can you draw to verify?
OpenStudy (triciaal):
my guess would be like @satellite73 difference of squares to be applied
OpenStudy (anonymous):
I think I am supposed to find two answers at the end, negative and positive?
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OpenStudy (triciaal):
before we can get to the end can you rewrite the problem in the draw or using parenthesis?
OpenStudy (triciaal):
|dw:1445224698053:dw|
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