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Write the sum using summation notation, assuming the suggested pattern continues. -10 - 2 + 6 + 14 + ... + 110
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@iambatman
@zepdrix
@ParthKohli
Hii @lxoser
see here first term =-10 second term =-2=-10+8 third term =6=-10+2*8
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let the nth term be 110 see the first term is -10 and common difference is 8 then -10+(n-1)8=110 implies (n-1)=15 implies n=16 so the required answer is
\[\sum_{n=1}^{16}(-10+(n-1)*8)\]
these are my options.. the one highlighted looks close to your answer.
@lxoser both are equivalent. if you put n in case of n-1, then the lower limit will change to 0/// yes it is correct
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