Question

Write the sum using summation notation, assuming the suggested pattern continues.

-10 - 2 + 6 + 14 + ... + 110

Answer 1

@iambatman

Answer 2

@zepdrix

Answer 3

@ParthKohli

Answer 4

Hii @lxoser

Answer 5

see here first term =-10
second term =-2=-10+8
third term =6=-10+2*8

Answer 6

let the nth term be 110
see the first term is -10 and common difference is 8
then -10+(n-1)8=110
implies (n-1)=15 implies n=16
so the required answer is

Answer 7

\[\sum_{n=1}^{16}(-10+(n-1)*8)\]

Answer 8

these are my options.. the one highlighted looks close to your answer.

Answer 9

@lxoser both are equivalent. if you put n in case of n-1, then the lower limit will change to 0/// yes it is correct