Question

x^2 + 2x - 48= 0 how can you solve this

Answer 1

here, we have to apply the standard formula:
\[x = \frac{{ - b \pm \sqrt {{b^2} - 4 \times a \times c} }}{{2 \times a}}\]
where \(a=1, b=2,c=-48\)

Answer 2

Let's solve your equation step-by-step.
x2+2x−48=0
Step 1: Factor left side of equation.
(x−6)(x+8)=0
Step 2: Set factors equal to 0.
x−6=0 or x+8=0
x=6 or x=−8

Answer 3

or you can factor it
find two numbers when you multiply them you should get product of AC (a=leading coefficient C =constant )
and when you add or subtract them you should get middle term ( b = coefficient of x term)

Answer 4

thank you guys

Answer 5

;)

Answer 6

(;
o^_^o

Answer 7

o^_^o