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solve \[\sqrt{x+2-2\ge7}\]
i got x>=-2
2-2=0 then you're left with \[\sqrt{x+0\ge7} = \sqrt{x \ge7}\]
I'm wrong?
or is there more to it..?
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I don't know what you mean by x>=-2....do you mean that x=-2? or that x>-2?
\[x \ge-2\]
Yeah, then you did it wrong because when doing working equations you go from left to write +2-2=0
And you solve inequalities similar to how you'd solve equations
where does the radicand stop?
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