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OpenStudy (anonymous):
derive y=xsin^-1x+square root (1-x^2)
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zepdrix (zepdrix):
Hey pie :) What's going on? Looking for derivative of this function?\[\large\rm y=x \arcsin x+\sqrt{1-x^2}\]Do you recall your arcsin(x) derivative?
OpenStudy (anonymous):
yeah, the sin deriv. is cos
zepdrix (zepdrix):
No no no you silly billy :O \(\large\rm (arcsin x)'\ne\cos x\) We have inverse sine, not sine.
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