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Calculus1 4 Online
OpenStudy (anonymous):

derive y=xsin^-1x+square root (1-x^2)

zepdrix (zepdrix):

Hey pie :) What's going on? Looking for derivative of this function?\[\large\rm y=x \arcsin x+\sqrt{1-x^2}\]Do you recall your arcsin(x) derivative?

OpenStudy (anonymous):

yeah, the sin deriv. is cos

zepdrix (zepdrix):

No no no you silly billy :O \(\large\rm (arcsin x)'\ne\cos x\) We have inverse sine, not sine.

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