Question

The length of a rectangle is 8 in. more than its width. The perimeter is 52 in.

What is the length of the rectangle?
in.

Answer 1

\[2(8 + w) + 2(w) = 52\]

solve for w

Answer 2

9

Answer 3

good!

Answer 4

YAY!!!!!!!!!!!!

Answer 5

Plug it into the value for \(L = 8 + w\)

Answer 6

2(8+w)+2(w)=52
(16+2w)+(2w)=52
16+4w=52
4w=36
w=4

Answer 7

L=8+4
L=12

Answer 8

@MJgirL1958 Sorry you're wrong ...

Answer 9

So the length is 12

Answer 10

ok im always wrong so ;)

Answer 11

write down what you solved

Answer 12

You would get w = 4 which is what @Abdullahbasra007 did.

And then you would have to do \( L = 8 + 4\) to get \(\color{green}{12}\)

Answer 13

OH ok i see it now thank you both

Answer 14

Anytime

Answer 15

\(\huge \scr WELCOME !\)

Answer 16

Thanks for the medal

Answer 17

welcome ;)