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Mathematics 15 Online
OpenStudy (calculusxy):

Quadratic formula...

OpenStudy (calculusxy):

\[\large \color {blue}{4n^2 = 6n - 2}\]

OpenStudy (calculusxy):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

show me what you have so far

OpenStudy (calculusxy):

Okay gimme a moment..

OpenStudy (calculusxy):

\[4n^2 = 6n - 2\] \[4n^2 + 2 = 6n\] \[4n^2 - 6n + 2 = 0\] \[\frac{ -(-6) \pm \sqrt{36 - 4(8)}}{ 2(4) } \rightarrow \frac{ 6 \pm \sqrt{4} }{ 8 } \rightarrow x = (1, 0.5)\]

jimthompson5910 (jim_thompson5910):

very nice, you have the correct answers I would keep things as a fraction instead of a decimal though n = 1 or n = 1/2

OpenStudy (calculusxy):

Thank you!

jimthompson5910 (jim_thompson5910):

you're welcome

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