Question

determine if the statement is true or false when evaluated 2x^2-4x+1>2x-x^2/4 when x=2

Answer 1

@satellite73

Answer 2

isn't is also true?

Answer 3

@jim_thompson5910

Answer 4

HI!!

Answer 5

guess we have to compute

Answer 6

hi

Answer 7

so what did you try narissa?

Answer 8

the first part =9 right?

Answer 9

put \(2\) in to \[2\times 2x^2-4x+1\] get \[2^2-4\times 2+1\]

Answer 10

so first half is this yea? \[ 2x^2-4x+1\] In that case, how did you get 9?

Answer 11

oops i made a typo

Answer 12

\[2\times 2^2-4\times 2+1\]

Answer 13

2*2=4^=16-4*2=8+1=9

Answer 14

oops not the correct order of operations

Answer 15

ah, \(2^2=4\) right? so what when you compute you need to remember order of ops.

Answer 16

square first, multiply second

Answer 17

\(2(2^2)\) is a nice way to think about it

Answer 18

im confused then the statement is false

Answer 19

well, let's figure it out first, so what do we get for the first part?

Answer 20

2*4=8

Answer 21

ok, so what does the first part = when we do order of ops correctly?

Answer 22

confused

Answer 23

ok, where at?

Answer 24

8-8+1 so it =1

Answer 25

yes, that is true

Answer 26

so now we need to do the second part

Answer 27

yaaa!

Answer 28

4-4=0

Answer 29

so its true

Answer 30

so is this the second half? \[2x-\frac{x^2}{4}\]

Answer 31

2*2=4/4-4=0

Answer 32

wait wait wait

Answer 33

ooops i think 3

Answer 34

first, I need you to confirm the second half :)

Answer 35

Is the eq I typed above accurate?

Answer 36

yes

Answer 37

ok and yea, 3 seems a little better there, just to be clear, how did you get 3?

Answer 38

2*2=4 then the fraction =4/4 so 4-1 =3

Answer 39

yea, now note the fraction is the same as division, so we are still following the order of ops here.

Answer 40

now last step is 1>3 true?