Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

What is the equation of this graphed line ? Please help me !!! - pic http://tinypic.com/r/2ex4qd5/8

OpenStudy (anonymous):

OpenStudy (sloppycanada):

y = mx + b

OpenStudy (sloppycanada):

So first thing first - can you find me two points?

OpenStudy (anonymous):

6 ?

OpenStudy (anonymous):

Just count rise over run

OpenStudy (anonymous):

count what?

OpenStudy (anonymous):

|dw:1445320070285:dw|

OpenStudy (anonymous):

rise refers to how many units you need to go up or down along the y-axis run refers to how many units you need to go left or right along the x-axis

OpenStudy (anonymous):

i got d

OpenStudy (anonymous):

y=5/2x

OpenStudy (anonymous):

that's right, do you know why?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

you can start the count at your origin (0,0) since the line passes perfectly through that intersection can you spot another coordinate where the line passes perfectly through?

OpenStudy (anonymous):

i am not sure but i get what u r saying. can u help me with one more? Please

OpenStudy (anonymous):

and by perfectly through, I mean at what coordinate does the line pass through a whole # for x-coordinate and a whole # for the y-coordinate?

OpenStudy (anonymous):

I can help you with another problem, but it might be better to understand how you got that answer before moving on

OpenStudy (anonymous):

What is the equation of the graphed line? Hint: Determine the slope of the line.

OpenStudy (sloppycanada):

Oh joy, line equations... y = mx +b

OpenStudy (anonymous):

lol this is why it's better to have an understanding of how you can find your answer since this question is using similar concepts

OpenStudy (anonymous):

i know all the slops and that it is a positive slope

OpenStudy (sloppycanada):

|dw:1445320452184:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!