Question

Solve 0<=Theta<2pi

Answer 1

hey

Answer 2

hey can you solve for sin(theta + 2pi/3)

Answer 3

brb

Answer 4

i got sin(theta+2pi/3)=1/2

Answer 5

plz ignore me
im sleepy not in a moO_Od to do math rn :(
and my brain isn't working :(

Answer 6

its fine :)

Answer 7

surji can you help me?

Answer 8

\[\sin \left( \theta+\frac{ 2 \pi }{ 3 } \right)=\frac{ 1 }{ 2 }=\sin (2 n \ pi+\frac{ \pi }{ 6 }),\sin \left( 2 n pi+\pi-\frac{ \pi }{ 6 } \right)\]
\[\theta=2n \pi+\frac{ \pi }{ 6 }-\frac{ 2 \pi }{ 3 },2 n \pi+\pi-\frac{ \pi }{ 6 }-\frac{ 2 \pi }{ 3 }\]
where n is an integer.
\[\theta=2n \pi-\frac{ 3\pi }{ 6 },~or~\theta=2 n \pi-\frac{ \pi }{ 2 }\]
put n=1
\[\theta=2 \pi-\frac{ \pi }{ 2 }=\frac{ 3 \pi }{ 2 }\]
\[\theta=2 n \pi+\frac{ 6 \pi-\pi-4 \pi }{ 6 }\]
\[\theta=2 n \pi-\frac{ \pi }{ 6 }\]
put n=1
\[\theta=2 \pi-\frac{ \pi }{ 6 }=\frac{ 11\pi }{ 6 }\]