Question

Can someone help me solve two functions? I will award a medal, and coins.

Answer 1

1.) What is the value of f(4) for the function f(x)=3x-5

Answer 2

2.) What is the value of f[g(4)] for the functions f(x)=2x+1 and g(x)=2x-5

Answer 3

Question #1
you have to replace \(x=4\) into your function, so, what is:
\(f(4)=3 \cdot 4 -5=...?\)

Answer 4

question #2
here we can write:
\(f(g(x))=2 g(x)+1=2 (2x-5)+1=...?\) please complete

Answer 5

I don't know how. @Michele_Laino

Answer 6

hint:
question #1
we have:
\(f(4)=12-5=...\)

Answer 7

question #2
I apply the distributive property of multiplication over addition, so i get:
\(f(g(x))=4x-10+1=4x-9\)
then I can write:
\(f(g(4))= 4 \cdot 4-9=16-9=..\)
please complete @sbuck98

Answer 8

7? @Michele_Laino

Answer 9

correct!

Answer 10

furthermore also \(f(4)=12-5=7\)

Answer 11

can you help me get the other answer?