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@Michele_Laino Is this one B?
correct!
please wait, it is not option B.
here the first derivative is: \[f'\left( x \right) = 3\left( { - {x^2} + 1} \right)\] and, it is an increasing function, if the subsequent condition holds: \[ - {x^2} + 1 > 0\] please, what is the solution of that inequality?
-x^2 > -1
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the solution is the subsequent set \(S\): \[S = \left\{ {x \in \mathbb{R}| - 1 < x < 1} \right\}\]
|dw:1445456064279:dw|
as we can see, at \(x=1\) we have a local, or relative maximum for f(x)
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