Question

Solve.
3/k+3 = 8/k-2

k = -1
k = 1
k = -6
k = 6

Answer 1

@netlopes1

Answer 2

if we multiply both sides by this quantity:
\((k+3)(k-2)\) we get:
\[\frac{3}{{\left( {k + 3} \right)}} \cdot \left( {k + 3} \right) \cdot \left( {k - 2} \right) = \frac{8}{{\left( {k - 2} \right)}} \cdot \left( {k + 3} \right) \cdot \left( {k - 2} \right)\]
please simplify