Can someone please help me.. I have no idea how to do this...

Question

celinegirl · Answer

attachment

celinegirl · Answer

plot your points...and you will notice that if you start at the y axis....and your slope is -2/3...that means start at (0,490)....go down 2 spaces then to the right 3 spaces, then down 2, then to the right 3...you will cross the x axis at (735,0).

love_333 · Answer

What is your question exactly?

celinegirl · Answer

I have to plot intercepts on the graph using that information

celinegirl · Answer

@Love_333

jim_thompson5910 · Answer

did you post the right picture? It doesn't match up

love_333 · Answer

Yeah, I feel the same as @jim_thompson5910 . The picture doesn't match the question..

celinegirl · Answer

@jim_thompson5910 im not sure.. maybe i have to create a new graph to match the information.

jim_thompson5910 · Answer

can you post the full screenshot of the entire problem?

love_333 · Answer

yes ^

love_333 · Answer

Will you try to post a full picture of all the problem?

celinegirl · Answer

Hold on! i posted the wrong this...

celinegirl · Answer

Graph the function. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology.

celinegirl · Answer

here's the function: f(x) = -2/3x + 490

jim_thompson5910 · Answer

ok if you were to replace x with 0, then the result would be 490, agreed?

celinegirl · Answer

@jim_thompson5910 yeah

jim_thompson5910 · Answer

so the y intercept is (0,490)

on the vertical y axis, mark a point at 490

celinegirl · Answer

@jim_thompson5910 sorry i know this is much but can you draw it?

jim_thompson5910 · Answer

|dw:1445467394202:dw|

jim_thompson5910 · Answer

|dw:1445467403908:dw|

jim_thompson5910 · Answer

490 is somewhere between 400 and 500, closer to 500

|dw:1445467464417:dw|

jim_thompson5910 · Answer

|dw:1445467474279:dw|