Question

THANK YU!

Answer 1

Well since we know

\[\large P = \frac{W}{\Delta t}\]

And we know Work is a force over some distance we have

\[\large P = \frac{Fx}{\Delta t}\]

Now think about the fact that a distance, over a change in time...sounds just like the velocity *speed* of an object doesnt it? so we have the alternative definition for power as

\[\large P = F\vec{v}\]

Answer 2

OHHHH! THANK YOU! I have been stuck on this for a while now!

Answer 3

Yeah no problem!

Answer 4

Could you help me with something???