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how do i write y=x2-8x-1 in vertex form
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vertex The point on an angle where the two sides intersect.
The vertex form of a quadratic function is given by f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola.
y=(x−4)2−17
the 2 should be ^2
y=(x-4)^2-17 or y+17=(x-4)^2
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Have you considered Completing the Square? Think on this: \((a+b)^{2} = a^{2} + 2ab + b^{2}\)
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