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Algebra 21 Online
OpenStudy (anonymous):

3x^2=x+4

Directrix (directrix):

What are the instructions? Solve for x or something else?

Directrix (directrix):

@Confused33

OpenStudy (seascorpion1):

3x^2-x-4=0 therefore:\[x=\frac{1\pm\sqrt{1+4*4*3}}{6}=\frac{1\pm7}{6}\] x=-1, x=4/3

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