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The volume v of a wooden beam is v=ls^2 where l is the length of the beam and s is the length of one side of its square cross section. If the volume of the beam is 1200 in ^3 and its length is 96 in what is the side length?
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\[\large V = ls^2\] We are given V to be 1200 and l to be 96 So we need just solve for 's' \[\large 1200 = 96\times s^2\] Meaning \[\large s^2 = \frac{1200}{96}\] Or \[\large s = \sqrt{\frac{1200}{96}}\]
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