Question

Solve the system of linear equations below.

2x + 3y = 2
x + 6y = 4

Answer 1

we will mark equation 1 as E1 and equation 2 as E2
first we will switch E1 with E2
2x + 3y = 2
x + 6y = 4

---> x + 6y = 4
2x + 3y = 2

now will do following E2=E2 - 2*E1

----> x + 6y =4 ----> x + 6y = 4
(2-2)x + (3-2*6)y =2 -2*4 0*x + -9y = -6
now we will work only in the second equation
-9y =-6
y=6/9 =2/3

we will insert it in 2x + 3y = 2
2x +3 *(2/3) =2
2x +2 =2 /-2
2x=0
x=0
the solution will be (0,2/3)