can someone help me with calculus? I have absolutely no idea how to do it. Im not posting the question yet. will post when someone is comitted. thanks

Question

tkhunny · Answer

Not how it works.  You are the one who needs the commitment.  Post your problem.  Show YOUR best work and someone should help you.

anonymous · Answer

ok so:

$$f(x)=\frac{ 8 }{ 4-x } $$

has a vertical asymptote at:

y=8
x=4
x=8
y=0

anonymous · Answer

@netlopes1 can you help?

netlopes1 · Answer

Please... wait, ok?

anonymous · Answer

ok sorry

tkhunny · Answer

Where is the denominator zero without the numerator also being zero?

tkhunny · Answer

You missed the "Show YOUR best work" part."

anonymous · Answer

is f(x) = 0?

anonymous · Answer

nevermind

netlopes1 · Answer

This is a rational function. More to the point, this is a fraction. Can you have a zero in the denominator of a fraction? No. So if I set the denominator of the above fraction equal to zero and solve, this will tell me the values that x cannot be 4, ok?

netlopes1 · Answer

So, you can draw the vertical asymptote as a dashed line to remind you not to graph there, in our case a line x=4

netlopes1 · Answer

Thanks for your trust....