Question

Graph the function using its vertex, axis of symmetry, and intercepts,
f(x)=x^2+2x-8

Answer 1

I got the vertex to be (-1,-9) is that right?
Then I got the intercepts as (2,0) (-4,0) and (0,-8)

Answer 2

These are really good websites I use http://mathpapa.com/algebra-calculator.html & http://www.wolframalpha.com/input/?i=f%28x%29%3Dx^2%2B2x-8 hopefully this will help you. :)

Answer 3

Thanks.