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Mathematics 12 Online
OpenStudy (anonymous):

Determine, without graphing, whether the given quadratic function has a maximum value or minimum value and then find that value. f(x)= -12x^2 -2x -5

OpenStudy (fibonaccichick666):

Have you done derivatives yet?

OpenStudy (anonymous):

no.

OpenStudy (fibonaccichick666):

ok, so then, you want to find the vertex of the parabola and figure out if the cup is up or down

OpenStudy (anonymous):

The graph opens Down

OpenStudy (fibonaccichick666):

ok, so is the vertex going to be a maximum or a minimum if it opens down?

OpenStudy (anonymous):

Maximum

OpenStudy (anonymous):

so then what?

OpenStudy (fibonaccichick666):

good, now. You need to find the vertex of the parabola

OpenStudy (anonymous):

Which is (H, K)

OpenStudy (fibonaccichick666):

You will need to put the equation into vertex form http://hotmath.com/hotmath_help/topics/vertex-of-a-parabola.html

OpenStudy (fibonaccichick666):

and find the values of h and k

OpenStudy (anonymous):

Okay, I found the vertex so now what?

OpenStudy (fibonaccichick666):

that's it.

OpenStudy (fibonaccichick666):

the vertex is the maximum in this case

OpenStudy (anonymous):

But that's not the Maximum or Minimum??

OpenStudy (anonymous):

I got (-0.083, -4.9167)

OpenStudy (fibonaccichick666):

in a parabola, the vertex is either the absolute maximum or absolute minimum

OpenStudy (fibonaccichick666):

I don't see that as being right. It shouldn't be that decimally

OpenStudy (fibonaccichick666):

so, give me a moment to see.

OpenStudy (fibonaccichick666):

ohk, I stand corrected. That is right

OpenStudy (fibonaccichick666):

nice job, and that's all there is

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