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Find a cubic function with the given zeros. 7, -3, 2
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They should all zero out the function, so we can write: \[f(x) = (x - 7)(x + 3)(x - 2)\] so at any of this parameters the value will be 0. Now we'll get rid of the parentheses: \[f(x) = x^3-6 x^2-13 x+42\]
Refer to the attachment.
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