Question

Use pseudocode to specify a recursive algorithm to compute the nth value of the harmonic series, for some integer n

Answer 1

I'm not certain that I understand the math, but this Python does what I expect, (that we go from 1...n):

>>> def harmonic( n ):
... if( n < 1 ):
... return 0.0
... else:
... return( harmonic( n - 1.0 ) + ( 1.0 / n ) )
...
>>> n = 3.0
>>> harmonic( n )
1.8333333333333333
>>> n = 4.0
>>> harmonic( n )
2.083333333333333
>>> n = 5.0
>>> harmonic( n )
2.283333333333333

You can pseudo it up.