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@Michele_Laino So I think it is B or D?
like in the prvious exercise,we start from this formula: \[y = \frac{1}{{x - 2}}\] and we have to express \(x\) as a function of \(y\)
previous*
So x = 1/y-2 ?
taking the inverse of both sides, I get: \[x - 2 = \frac{1}{y}\] now, if I add \(2\) to both side I get: \[x - 2 + 2 = \frac{1}{y} + 2\] please simplify
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x=1/y+2
correct! Now I change \(x\) with\({f^{ - 1}}\left( y \right)\), so I write this: \[{f^{ - 1}}\left( y \right) = \frac{1}{y} + 2\]
1/(y-2)****
finally, we have to replace \(y\) with \(x\)
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