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evaluate 2(3x-y) when a)x=10 y=-3 b)x=-3 y=10 c)x=-3 y=-10
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@Austin1617
first do 3*x when x=10 what is 3*x ?
should the first one look like this 2(3+10+3)=66
30
so now you have 2*(30-y) now do 30 - y when y is -3 30 - (-3) is what ?
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is it -33
two minuses make a plus 30 - -3 is the same as 30+3
oh 33*2 right?
yes
66
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thank u
yes. do you get the general idea? for the next problem b)x=-3 y=10 we can swap in those numbers into 2(3x-y) to get 2*(3*-3 - 10)
I put in the * to show multiplication because we know 3x means 3*x but if we put in -3 for x without the multiply sign: 3-3, that is wrong we really would want 3* -3 which is -9
-38?
yes
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thanks
would c look like this 2(-9+10=2
yes, for c) you get 2*1= 2
thanks
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