Hi can somebody help me with this ; find the equation of tangent line to the curve y=2sinx+3cosx x=0 plsssss
using calculus ?
\(\large\color{black}{ \displaystyle f'(x)=? }\)
So if you're given \(x=3\) , your point of tangency will be \((3~,~ f(3)\)
Then you find f'(x) which is your slope at the point of tangency, You find the slope at the point x=3, then use point slope form: \(y-y_0 = f'(x) (x-x_0)\) to find the equation of the line.
Does that make any sense?
Sandra, there is no reason to stay silent if you want to get help. If you don't understand something, then please ask.
ok, bye
sorry im trying to understant /how this web site works :(
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