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OpenStudy (anonymous):
Can anyone tell me my mistake?
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OpenStudy (anonymous):
This is the question:
OpenStudy (anonymous):
what you need is an ethyl bromide and an acetate ion. The ethyl bromide falls under an alkyl bromide because the only other compounds in the structure are carbons and hydrogens whereas the other reagent is bromine as the r group of an acyl group which contains a c double bonded to an o, ch3 and an r group
OpenStudy (anonymous):
Would you be able to show me how that would look? I am having trouble drawing it.
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