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pooja195 (pooja195):
Multiply...
\[\huge~\rm~2x^2−2x−24=12 \]
pooja195 (pooja195):
Are you learning about qudratic formula?
OpenStudy (anonymous):
as long i find x its fine
pooja195 (pooja195):
Im not sure what lesson this is... what lesson is this? Like what are you learning about/
OpenStudy (anonymous):
distributive axiom
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pooja195 (pooja195):
Multiply...
\[\huge~\rm~2x^2−2x−24=12\]
I assume you are doing the quadratic formula
we need to set the equation = to 0
so we subtract 12 from both sides
-24-12=?
OpenStudy (anonymous):
im still paying attention
pooja195 (pooja195):
Really?
Coz i asked u a question still havent gotten an answer
OpenStudy (anonymous):
-12
pooja195 (pooja195):
We are subtracting.
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pooja195 (pooja195):
-36
OpenStudy (anonymous):
i just got the answer sorry read the problem wrong
pooja195 (pooja195):
\[\huge~\rm~2x^2−2x−36=0\]
From here i am unsure of what to do i think we use the quadratic formula @Nnesha can you confirm please??
pooja195 (pooja195):
@becca1 are you fimilir with this?
\[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
OpenStudy (anonymous):
nope
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OpenStudy (anonymous):
@pooja195 hello
pooja195 (pooja195):
Hold on
Nnesha (nnesha):
if the question is \[\large~\rm~\frac{ 2x-8 }{ 3 }=\frac{ 4 }{ 3+x}\]
then yes that looks good to me
OpenStudy (anonymous):
no it isnt
pooja195 (pooja195):
BRUH
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Nnesha (nnesha):
\[\frac{ 2x-8 }{ 3} =\frac{ 4 }{ 3 }+x\] like this ?
pooja195 (pooja195):
Why didnt u tell me it wasnt the correct question?????
Nnesha (nnesha):
or maybe \[2x-\frac{8}{3}=\frac{ 4 }{ 3 }+x\] like this ?
pooja195 (pooja195):
And she left
OpenStudy (paki):
@pooja195 yeah you are right....
2x^2−2x−36=0
go ahead by using quadratic formula... and find "x" pairs...
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pooja195 (pooja195):
@paki she said its not the correct question ;-;
Nnesha (nnesha):
you should mentioned it before when she posted a first comment
anywyz put parentheses is it (2x-8)/3 or 2x-(8/3)
pooja195 (pooja195):
@becca1 should have told me it wasnt the correct problem before I started explaining things.
OpenStudy (texaschic101):
you about to scream now ?....lol
pooja195 (pooja195):
@texaschic101 I dont find u the least bit funny.
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OpenStudy (texaschic101):
I know....lol :)
OpenStudy (texaschic101):
I am sorry..I did not mean anything by it...I can understand your frustration
pooja195 (pooja195):
Its all good :P sorry for the attitude :P
OpenStudy (texaschic101):
no problem...I would have been upset too
OpenStudy (anonymous):
@pooja195
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