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Mathematics 18 Online
OpenStudy (anonymous):

2x-8/3=4/3+x

pooja195 (pooja195):

Are we trying to find the value of x?

OpenStudy (anonymous):

yes

pooja195 (pooja195):

\[\huge~\rm~\frac{ 2x-8 }{ 3 }=\frac{ 4 }{ 3+x}\] Start by "cross multiplying"

pooja195 (pooja195):

\[\huge~\rm~(2x−8)*(3+x)=(4)*(3) \]

OpenStudy (anonymous):

then what

pooja195 (pooja195):

Multiply... \[\huge~\rm~2x^2−2x−24=12 \]

pooja195 (pooja195):

Are you learning about qudratic formula?

OpenStudy (anonymous):

as long i find x its fine

pooja195 (pooja195):

Im not sure what lesson this is... what lesson is this? Like what are you learning about/

OpenStudy (anonymous):

distributive axiom

pooja195 (pooja195):

Multiply... \[\huge~\rm~2x^2−2x−24=12\] I assume you are doing the quadratic formula we need to set the equation = to 0 so we subtract 12 from both sides -24-12=?

OpenStudy (anonymous):

im still paying attention

pooja195 (pooja195):

Really? Coz i asked u a question still havent gotten an answer

OpenStudy (anonymous):

-12

pooja195 (pooja195):

We are subtracting.

pooja195 (pooja195):

-36

OpenStudy (anonymous):

i just got the answer sorry read the problem wrong

pooja195 (pooja195):

\[\huge~\rm~2x^2−2x−36=0\] From here i am unsure of what to do i think we use the quadratic formula @Nnesha can you confirm please??

pooja195 (pooja195):

@becca1 are you fimilir with this? \[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

@pooja195 hello

pooja195 (pooja195):

Hold on

Nnesha (nnesha):

if the question is \[\large~\rm~\frac{ 2x-8 }{ 3 }=\frac{ 4 }{ 3+x}\] then yes that looks good to me

OpenStudy (anonymous):

no it isnt

pooja195 (pooja195):

BRUH

Nnesha (nnesha):

\[\frac{ 2x-8 }{ 3} =\frac{ 4 }{ 3 }+x\] like this ?

pooja195 (pooja195):

Why didnt u tell me it wasnt the correct question?????

Nnesha (nnesha):

or maybe \[2x-\frac{8}{3}=\frac{ 4 }{ 3 }+x\] like this ?

pooja195 (pooja195):

And she left

OpenStudy (paki):

@pooja195 yeah you are right.... 2x^2−2x−36=0 go ahead by using quadratic formula... and find "x" pairs...

pooja195 (pooja195):

@paki she said its not the correct question ;-;

Nnesha (nnesha):

you should mentioned it before when she posted a first comment anywyz put parentheses is it (2x-8)/3 or 2x-(8/3)

pooja195 (pooja195):

@becca1 should have told me it wasnt the correct problem before I started explaining things.

OpenStudy (texaschic101):

you about to scream now ?....lol

pooja195 (pooja195):

@texaschic101 I dont find u the least bit funny.

OpenStudy (texaschic101):

I know....lol :)

OpenStudy (texaschic101):

I am sorry..I did not mean anything by it...I can understand your frustration

pooja195 (pooja195):

Its all good :P sorry for the attitude :P

OpenStudy (texaschic101):

no problem...I would have been upset too

OpenStudy (anonymous):

@pooja195

OpenStudy (anonymous):

its supposed to be|dw:1445803993649:dw|

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