Question

Math question

Answer 1

@SolomonZelman

Answer 2

Ok, what "y varies jointly as x and cube root of z" means is:

\(\large\color{black}{ \displaystyle y=k\times x\times \sqrt[3]{z} }\)

Answer 3

\(\large\color{black}{ \displaystyle 120=k\times 3\times \sqrt[3]{8} }\)
\(\large\color{black}{ \displaystyle 120=k\times 6 }\)
\(\large\color{black}{ \displaystyle 20=k }\)

Answer 4

Thanks, yes. I got it :)

Answer 5

that is not it

Answer 6

You have found k=20.

\(\large\color{black}{ \displaystyle y=20\times x\times \sqrt[3]{z} }\)

Answer 7

now, you need to find y, when x=4 and z=27.

Answer 8

plug in for \(x\) and for \(z\) and calculate the \(y\).