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Forces in the horizontal are equal so I got the cosine of the angle for Charlie’s force. I’m thinking that since there can be two angles that give the same result those two angles are the two possible directions for equilibrium, in which case the magnitude of Betty’s force will stay the same.
Is that right?
".odt" that is, presumably, an Open Document attachment, but i would never open that online. Fuddy duddy but that is not a good way to share.......
I hope that's better @IrishBoy123
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