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first distribute both sides: 4*(2x+3)=2*(3x-4) 8x+12=6x-8 2x=-24 x=-12
woops
4*(2x+3)=2*(3x-4) 8x+12=6x-8 2x=-20 x=-10
4*(2x+3)=2*(3x-4) 8x+12=6x-8 2x=-8-12 2x=-20 x=-10 substitute: 4*(2*-10 + 3)=2*(3*-10 - 4) 4*(-20+3)=2*(-30-4) 4*-17=2*-34 -68=-68 any more questions?
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