Question

Express the complex number in trigonometric form.

-6 + 6√3

i know to get r its √a^2+b^2
which is √36+324, so √360...

but now what????????

Answer 1

\(-6 + \color{red}i \;6\sqrt{3} = 12(-\dfrac{1}{2} + \dfrac{\sqrt{3}}{2})\)

Answer 2

12 (cos2pi/3 + sin2pi/3) ????