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Mathematics 19 Online
OpenStudy (math2400):

can anyone check these answers - probability

OpenStudy (math2400):

OpenStudy (math2400):

@amistre64

OpenStudy (amistre64):

ok, ive reviewed it, now can you tell me your thought process that led you to the solutions you chose?

OpenStudy (math2400):

aww so there are some wrong? lol

OpenStudy (amistre64):

not saying if they are right or wrong yet, but i want to know why you did what you did :)

OpenStudy (math2400):

so for P(A) i used (0.28+0.09+0.04+0.07)

OpenStudy (math2400):

P(B)= 0.52+0.28+0.09

OpenStudy (math2400):

and i say false because P(A) and P(B) overlap

OpenStudy (amistre64):

you did very well then :) i agree with your conclusions

OpenStudy (math2400):

thank u soo much! can u check one more?

OpenStudy (amistre64):

perhaps

OpenStudy (math2400):

OpenStudy (math2400):

@amistre64 are u looking at it? :)

OpenStudy (amistre64):

im drawing up a table ... and working some calculations im not familiar with working with the specifity and sensitivity numbers, but here is what i get

OpenStudy (amistre64):

.9985a + .006b = .01, .0015a + .994b = .99

OpenStudy (math2400):

i'm pretty sure the ones before are right. im just not sure about the last on tho. the multiple choice one

OpenStudy (amistre64):

can you tell me how you worked your solutions?

OpenStudy (math2400):

is this one correct: This conditional probability tells us how likely it is that someone has HIV if that randomly chosen person has received a positive test result.

OpenStudy (math2400):

?

OpenStudy (amistre64):

your conditional question sounds good to me, the likelihood that they have HIV given that they were randomly selected form those who test +

OpenStudy (amistre64):

just for clarification, my table got mixed around and is not accurate :)

OpenStudy (math2400):

no worries! i actually submitted it and it was correct. thanks for your help :)

OpenStudy (amistre64):

:) youre welcome

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