Question

HI everyone i'm new here ! please help me !
can anyone solve this lim?
lim[2sinx]=

Answer 1

Hey there! :)
\(\Large\bf \color{#CC0033}{\text{Welcome to OpenStudy! :)}}\)

Answer 2

What is the limit approaching?
Infinity? zero?

Answer 3

And do the brackets mean anything?
Greatest integer function?
Or you were just using those for normal brackets? :)

Answer 4

the main question is about
Discontinuity and its usual brackets

Answer 5

sorry my english is not very good

Answer 6

\[\large\rm \lim_{x\to?}~2\sin x\]

Answer 7

its about number of discontinuity of function

Answer 8

Hmm :d

Answer 9

you know what i mean?

Answer 10

Discontinuities in the function

Answer 11

The limit does not converge as \(\large\rm x\to\infty\) or as \(\large\rm x\to-\infty\).
Is that what you mean maybe? :)

I don't think we have any discontinuities,
because sinx is continuous over all the real numbers.

So did you mean diverge instead maybe? :o
Hmm thinking..

Answer 12

There is an "Attach File" button at the bottom of this text box.
Maybe you can attach a screenshot of the original problem? :)
Or it's not in English? :3

Answer 13

Chart Dayrhchnd bracket function within half a point of discontinuity ?

Answer 14

translate it

Answer 15

i think this is only in our country :)))

Answer 16

its not enlish

Answer 17

Oh boy XD

Answer 18

Hmm, I don't know :c sorry.
@ganeshie8
maybe someone can translate and figure this out hehe

Answer 19

Chart bracket function within a semicircle is a point of continuity (sorry this is correst)

Answer 20

ok thanks alot