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To two decimal places, find the value of k that will make the function f(x) continuous everywhere.
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a. 11.00 b. -2.47 c. -0.47 d. None of these d right?
no, not choice d
what y?
-0.47?
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continuous means no "jumps" the two lines y= 3x+k and y = kx^2-5 must "match up" at x= -4 i.e. have the same y value in other words we need 3x+ k = k x^2 - 5 when x= -4 that means -12 + k = 16k - 5 -7 = 15 k -7/15 = k
thank you
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