As the angular speed decreases, the period of revolution increases.. am i right?

Question

owlet · Answer

I based from the formula $\LARGE \omega = \frac{2 \pi}{T}$

angular speed is inversely proportional to the period, so I think angular speed decreases when the period of revolution increases.

matt101 · Answer

Yes. Think about what's actually happening - when you decrease the angular speed, it means the object is rotating more slowly (sweeps through a smaller angle per unit time). If it rotates more slowly, it takes longer for it to complete a full revolution. The period of revolution has gone up!

owlet · Answer

thanks again :)