Question

As the angular speed decreases, the period of revolution increases.. am i right?

Answer 1

I based from the formula \(\LARGE \omega = \frac{2 \pi}{T}\)

angular speed is inversely proportional to the period, so I think angular speed decreases when the period of revolution increases.

Answer 2

Yes. Think about what's actually happening - when you decrease the angular speed, it means the object is rotating more slowly (sweeps through a smaller angle per unit time). If it rotates more slowly, it takes longer for it to complete a full revolution. The period of revolution has gone up!

Answer 3

thanks again :)