Question

find the exact value of the equation in the interval [0, 2pi)
sin3theta-sin6theta=0

Answer 1

you could use double angle identity
\[\sin(6 \theta)=\sin(2 \cdot 3 \theta)=2 \sin(3 \theta) \cos(3 \theta)\]

Answer 2

plug and then factor

Answer 3

how would i factor that ?

Answer 4

both terms have a common factor of sin(3 theta)