Question

Problem 1A-6a. Is the solution right? Shouldn't there be a 1 over sqrt(3), not vice-versa? for tan c

Answer 1

The issue solved: it's the \[\frac{ \sqrt{3} }{ 1}\] that should be evaluated, not vice-versa, since we input in a*sin x + b*cos x the values of cos y and sin x, respectively. (a = cosy y; b = sin y)