Question

Find the value of B: -12Axe^(-x)+2Ae^(-x)-6Be^(-x)=-6xe^(-x)

Answer 1

I know that A=1/2 but what's B?

Answer 2

@ganeshie8 @mathstudent55 @ParthKohli @texaschic101

Answer 3

@phi @Hero @Directrix

Answer 4

you should factor out a 2 e^(-x) from each term on both sides and then cancel
or if you like, multiply both sides by 1/2 e^x
what do you get ?

Answer 5

after dividing by 2e^(-x)
-12Axe^(-x)+2Ae^(-x)-6Be^(-x)=-6xe^(-x)
you get
-6Ax +A -3B= -3x
now match up corresponding terms
-6Ax = -3 x
so A = 1/2
also
-3B+A = 0
so you can solve for B.

Answer 6

Thank you!